Question

What is correct formulation of Hardy-Weinberg law?

• A. $p^2+2pq+q^2=1$
• B. $p^2+pq+q^2=1$
• C. $p^2+2pq+q^2=0$
• D. $p^2+pq+q^2=0$

Answer 1

Answer: (A)

$p^2+2pq+q^2=1$

The Hardy-Weinberg equation is given by,

p2 + 2pq + q2 = 1

Here, p and q represent the individual allele frequencies.

Therefore, p2= frequency of homozygous condition represented by p.

q2= frequency of homozygous alleles represented by q.

2pq = frequency of heterozygous condition.

So, the correct answer is 'p2 + 2pq + q2 = 1'