What is correct order of stability of the following carbocations:
A. $+ C H_{2} - C H_{3}$
B. $+ C H_{2} - C H_{2} C l$
C. $+ C H_{2} - C H C l_{2}$
D. $+ C H_{2} - C C l_{3}$

A > B > C > D

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A > C > B > D

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D > C > B > A

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D > B > C > A

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Solution

The correct option is A $A > B > C > D$
Since $C l$ is an electron withdrawing group, it shows $- I$ effect.
Higher the number of $C l$ atoms attached, higher the stability of carbocation, because it neutralizes the positive charge more.
In option D, there are maximum number of $C l$ atoms attached to carbon.
So it will be the most stable, followed by C then B and A which is least stable.

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Similar questions

+ C H_{2} - C H_{3}

+ C H_{2} - C H_{2} C l

+ C H_{2} - C H C l_{2}

+ C H_{2} - C C l_{3}

The correct order of stability of the following carbanions is:

$(C H_{3})_{3} C^{-},^{-} C C l_{3}, (C H_{3})_{2} C H^{-}, C_{6} H_{5} - C H_{2}^{-}$

(A) C H_{3} - C H_{2} - C | C O O H H - - C H - C H_{3}

(B) C H_{3} - C | C O O H H - C H_{2} - - C H - C H_{3}

(C) C | C O O H H_{2} - C H_{2} - C H_{2} - - C H - C H_{3}

The correct order of stability of the following carbanions is:

$(C H_{3})_{3} C^{-},^{-} C C l_{3}, (C H_{3})_{2} C H^{-}, C_{6} H_{5} - C H_{2}^{-}$

C H_{3} - O (A) - + C H_{2}, C H_{3} - N H (B) - + C H_{2}, C H_{3} - S (C) - + C H_{2}

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