What is curl of the vector field 2x2y^i+5z2^j−4yz^k?
A
−14z^i−2x2^k
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B
6z^i+4x^j−2x2^k
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C
6z^i+8xy^j+2x2y^k
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D
−14z^i+6y^j+2x2^k
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Solution
The correct option is A−14z^i−2x2^k Curl of the vector field = ∣∣
∣
∣∣^i^j^k∂∂x∂∂y∂∂z2x2y5z2−4yz∣∣
∣
∣∣
= ^i(-4z-10z)-^j(0-0) +^k(0−2x2)
= −14z^i−2x2^k