Question

What is $\frac{7}{11}\times \frac{33}{49}\times \frac{14}{44}+\frac{19}{22}=?$

Answer 1

$\frac{7}{11}\times \frac{33}{49}\times \frac{14}{44}+\frac{19}{22}$
$=\frac{3}{7}\times \frac{14}{44}+\frac{19}{22}$
$=\frac{3}{22}+\frac{19}{22}$
$=\frac{22}{22}$
$=1$