What is x2 - 3x - 2x2 - 5x - 6-x2 - 5x - 4x2 - 7x - 12 equal to

The correct option is B 1 x^2 3x + 2x^2 5x + 6×x^2 7x + 12x^2 5x + 4 = (x 2)(x 1)× (x 3)(x 4)(x 2)(x 3)× (x 4)(x 1) = 1 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Subtraction of Rational Expressions

What is x2 ...

Question

What is $\frac{x^{2} - 3 x + 2}{x^{2} - 5 x + 6} \div \frac{x^{2} - 5 x + 4}{x^{2} - 7 x + 12}$ equal to

\frac{x + 3}{x - 3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{x + 1}{x - 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

Now in each of the pairs of polynomials given below, check whether the first is a factor of the second:

(i) x + 1, x³ − 1

(ii) x − 1, x³ + 1

(iii) x + 1, x³ + 1

(iv) x² − 1, x⁴ − 1

(v) x − 1, x⁴ − 1

(vi) x + 1, x⁴ − 1

(vii) x − 2, x² − 5x + 1

(viii) x + 2, x² + 5x + 6

(ix)

(x) 1.3x − 2.6, x² − 5x + 6

\frac{x^{2} - 3 x + 2}{x^{2} - 5 x + 6} \div \frac{x^{2} - 5 x + 4}{x^{2} - 7 x + 12}

\sqrt{3} x^{2} - 2 x + \frac{1}{2} = 0

x^{2} + \frac{1}{x^{2}} = 5

x - \frac{3}{x} = x^{2}

2 x^{2} - \sqrt{3 x} + 9 = 0

x^{2} - 2 x - \sqrt{x} - 5 = 0

x + \frac{1}{x} = 1

{(x + \frac{1}{x})}^{2} = 3 (x + \frac{1}{x}) + 4

x + \frac{1}{x} = x^{2}, x \neq 0

l i m x \to 2 [\frac{1}{x^{2} - 5 x + 6} + \frac{1}{{2 x}^{2} - 7 x + 6}]

Given

$\frac{(x^{2} - 5 x + 6)}{(x^{2} - 7 x + 12)} = \frac{(x^{2} - x - 6)}{(x^{2} + 7 x + 10)}$ , then the value of $x$ is

Join BYJU'S Learning Program