1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Chemistry
Gibb's Energy and Nernst Equation
What is ECe...
Question
What is
E
0
C
e
l
l
if:
2
C
r
+
3
H
2
O
+
3
O
C
l
−
→
2
C
r
3
+
+
3
C
l
−
+
6
O
H
−
C
r
3
+
+
3
e
−
→
C
r
,
E
0
=
−
0.74
V
O
C
l
−
+
H
2
O
+
2
e
−
→
C
l
−
+
2
O
H
−
E
0
=
0.94
V
Open in App
Solution
E
0
c
e
l
l
=
(
E
0
C
r
/
C
r
3
+
+
E
0
O
C
l
−
/
C
l
−
)
=
(
0.74
+
0.94
)
=
1.68
V
Suggest Corrections
0
Similar questions
Q.
What will be the
E
0
value for the given half cell reaction?
C
r
2
+
(
a
q
)
+
2
e
−
→
C
r
(
s
)
Given:
E
0
value for the half cell reaction,
C
r
3
+
(
a
q
)
+
e
−
→
C
r
2
+
(
a
q
)
;
E
0
=
−
0.41
V
C
r
3
+
(
a
q
)
+
3
e
−
→
C
r
(
s
)
;
E
0
=
−
0.74
V
Q.
Electra - "Hmm, this looks tricky"
At
25
∘
C
,
C
r
3
+
+
e
−
→
C
r
2
+
,
g
i
v
e
n
E
0
=
−
0.424
V
C
r
2
+
+
2
e
−
→
C
r
(
s
)
,
g
i
v
e
n
E
0
=
−
0.9
V
F
i
n
d
E
0
a
t
25
∘
C
f
o
r
C
r
3
+
(
a
q
)
+
3
e
−
→
C
r
(
s
)
Electra was completely stumped. Seems like you need a way to add electrode potentials. Please tell her the answer.
Q.
2
O
H
−
+
2
O
C
N
−
+
3
O
C
l
−
→
2
C
O
3
2
−
+
N
2
+
3
C
l
−
+
H
2
O
This is the balanced chemical equation of the reaction in which medium?
Q.
Two half reactions are given as follows:
2
e
−
+
H
+
+
H
5
I
O
6
→
I
O
3
−
+
3
H
2
O
C
r
→
C
r
3
+
+
3
e
−
Final balanced reaction is:
Q.
The zinc/silver oxide cell is used in electric watches. The reaction is as follows
Z
n
+
2
+
2
e
⟶
Z
n
;
E
0
=
−
0.76
V
A
g
2
O
+
H
2
O
⟶
2
A
g
+
2
O
H
−
;
E
0
=
0.344
V
If
F
is
96500
m
o
l
−
1
, then
Δ
G
0
of the cell is:
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Gibb's Energy and Nernst Equation
CHEMISTRY
Watch in App
Explore more
Gibb's Energy and Nernst Equation
Standard XII Chemistry
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app