Question

What is energy released in the $\beta -decayof{}^{32}P{\to }^{32}S?$(Given:atomic masses:31.97391 u for $\left({}^{32}Pand31.97207ufo{r}^{32}S\right)$

• A. -1.2 MeV
• B. + 1.7 MeV
• C. +2.1 MeV
• D. -0.9 Mev

Answer 1

The correct option is B + 1.7 MeV

Released energy will be corresponding the $mass$ $defect$ $\text{which is difference in mass of parent nuclei and daughter nuclei}$

so mass defect is $31.97391u-31.97207u=0.00184u=0.00184\times 931Mev=1.7Mev$

as $1u=931MeV$ of $energy$.

Option B is correct.