What is equivalent Celsius value for 55-F-12-78-C23-78-C11-78-C21-78-C

The correct option is A 12.78 ^∘CGiven: F = 55 ^∘F, C = ? We know that, F = 95 C + 32 Solving for C, we get: nbsp; C = 59(F 32) Therefore, for F = 55 ^∘F, ...

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Standard X

Physics

Scales of Temperature

What is equiv...

Question

What is equivalent Celsius value for $55^{\circ} F$ ?

12.78^{\circ} C

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11.78^{\circ} C

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21.78^{\circ} C

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23.78^{\circ} C

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Solution

The correct option is A $12.78^{\circ} C$
Given: F = $55^{\circ} F$ , C = ?

We know that, F = $\frac{9}{5}$ C + 32

Solving for C, we get:

C = $\frac{5}{9}$ (F - 32)

Therefore, for F = $55^{\circ} F$ , we have:

C = $\frac{5}{9}$ (55 - 32)

i.e. C = $12.78^{\circ} C$

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Similar questions

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Q. What is equivalent Celsius value for

55^{\circ} F

What is the equivalent temperature of 0 degree Celsius in Fahrenheit scale?

Q. Temperature in Celsius scale is given as

40^{\circ} C

, find its equivalent temperature in Fahrenheit scale (

^{\circ} F

) :

C = \frac{5}{9} (F - 32)

The equation above shows how a temperature F, measured in degrees Fahrenheit, relates to a temperature C, measured in degrees Celsius. Based on the equation, which of the following must be true?
I. A temperature increase of

1

degree Fahrenheit is equivalent to a temperature increase of

\frac{5}{9}

degree Celsius.
II. A temperature increase of

1

degree Celsius is equivalent to a temperature increase of

1.8

degrees Fahrenheit.
III. A temperature increase of

\frac{5}{9}

degree Fahrenheit is equivalent to a temperature increase of

1

degree Celsius

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What is equivalent Celsius value for 55 ∘F?

The correct option is A 12.78 ∘CGiven: F = 55 ∘F, C = ? We know that, F = 95 C + 32 Solving for C, we get: C = 59(F - 32) Therefore, for F = 55 ∘F, we have: C = 59(55 - 32) i.e. C = 12.78 ∘C

What is equivalent Celsius value for $55^{\circ} F$ ?

The correct option is A $12.78^{\circ} C$
Given: F = $55^{\circ} F$ , C = ?

We know that, F = $\frac{9}{5}$ C + 32

Solving for C, we get:

C = $\frac{5}{9}$ (F - 32)

Therefore, for F = $55^{\circ} F$ , we have:

C = $\frac{5}{9}$ (55 - 32)

i.e. C = $12.78^{\circ} C$