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Byju's Answer

Standard XII

Chemistry

Gases in Liquids

What is Henry...

Question

What is Henry's constant for neon dissolved in water given $C_{N e} = 23.5 m L / L$ solution and STP volume ( $22, 414$ mL/mole gas) and pressure (1 atm)?

0.00105

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0.11004

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0.00115

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0.00015

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Solution

The correct option is A $0.00105$
1 L of solution contains 23.5 mL of neon which is equal to $23.5 \times \frac{1}{22414} = 0.001048$ moles at STP.
Thus the concentration of the solution is 0.001048M.
According to Henry's law, $S = K P$
$S$ is the solubility in moles per litre
$K$ is the henry's law constant
$P$ is the pressure in atm.
Substitute values in the above expression.
$0.001048 = K_{H} \times 1 a t m$
$K_{H} = 0.001048 L a t m^{- 1} = 0.00105 L a t m^{- 1}$

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What is Henry's constant for neon dissolved in water given CNe=23.5mL/L solution and STP volume (22,414 mL/mole gas) and pressure (1 atm)?

What is Henry's constant for neon dissolved in water given $C_{N e} = 23.5 m L / L$ solution and STP volume ( $22, 414$ mL/mole gas) and pressure (1 atm)?