What is hybridisation of $C o (N H_{3})_{4} C l_{2} C l$ ?

d^{2} s p^{3}

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s p^{3}

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d s p^{2}

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s p^{3} d

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Solution

The correct option is A $d^{2} s p^{3}$
$[C o (N H_{3})_{4} C l_{2}] C o^{3 +} \to d^{6} \to$ (refer to image)
Since $N H_{3}$ is strong field ligand when $C O (I I I)$ is there it causes pairing of all $d -$ electrons creating two inner vacant $d -$ orbital.

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