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Factors Affecting Rate Constant

What is Kc fo...

Question

What is K_c for the following equilibrium when the equilibrium concentration of each substance is: [SO₂]= 0.60 M, [O₂] = 0.82 M and [SO₃] = 1.90 M ?

2SO₂ (g) + O₂ (g) ⇌ 2SO₃ (g)

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Solution

The equilibrium constant (K_c) for the give reaction is:

Hence, K_cfor the equilibrium is.

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Similar questions

Q. For the reaction,

2 S O_{2 (g)} + O_{2 (g)} ⇌ 2 S O_{3 (g)}

K_{c}

when the equilibrium concentration of

[S O_{2}] = 0.60 M, [O_{2}] = 0.82 M

[S O_{3}] = 1.90 M

?

Q. For the equilibrium

2 S O_{2} (g) + O_{2} (g) ⇌ 2 S O_{3} (g)

the concentration of each substance at equilibrium is:

[S O_{2}] = 0.60 M, [O_{2}] = 0.82 M

[S O_{3}] = 1.90 M

_{c}

K_{c}

for the following equilibrium when the equilibrium concentration of each substance is:

[S O_{2}] = 0.60 M, [O_{2}] = 0.82 M

[S O_{3}] = 1.90 M

2 S O_{2} + O_{2} ⇌ 2 S O_{3}

Q. For the reaction,

2 S O_{2} (g) + O_{2} (g) ⇌ 2 S O_{3} (g)

K_{c}

when the equilibrium concentration of

[S O_{2}] = 0.60 M, [O_{2}] = 0.82 M a n d [S O_{3}] = 1.90 M

?

K_{c}

for the following equilibrium when the equilibrium concentration of each substance is:

[S O_{2}] = 0.60 M, [O_{2}] = 0.82 M

[S O_{3}] = 1.90 M

2 S O_{2} + O_{2} ⇌ 2 S O_{3}

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