What is meant by saying that the latent heat of vaporisation of water is 22.5 $\times 10^{5}$ J/Kg?

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Solution

It means that 22.5 $\times 10^{5}$ J of heat is required to change 1 Kg of water (at its boiling point, 100 $^{\circ}$ C into steam at the same temperature of $100^{\circ}$ C.

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Q. The latent heat of vaporisation of water is :
(a) 2.25 × 10⁶ J/kg
(b) 3.34 × 10⁶ J/kg
(c) 22.5 × 10⁴ J/kg
(d) 33.4 × 10⁵ J/kg

Q. What is meant by saying that the latent heat of fusion of ice is 3.34 × 10⁵ J/kg ?

Q. The latent heat of fusion of ice is :
(a) 33.4 × 10⁵ J/kg
(b) 22.5 × 10⁵ J/kg
(c) 33.4 × 10⁴ J/kg
(d) 22.5 × 10⁴ J/kg

Why is the latent heat of fusion of ice i.e 3.34×10⁵J/kg less than the latent heat of vapourisation i.e 22.5×10⁵J/kg? Particles of solids are more tightly packed than liquids so literally the should require more energy for separation than liquids.

Q. (a) Define the term 'latent heat of vaporisation' of a liquid. What is the value of the latent heat of vaporisation of water ?
(b) Draw a labelled diagram of the experimental set-up to study the latent heat of vaporisation of water.

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What is meant by saying that the latent heat of vaporisation of water is 22.5×105J/Kg?

It means that 22.5×105J of heat is required to change 1 Kg of water (at its boiling point, 100∘C into steam at the same temperature of 100∘C.

What is meant by saying that the latent heat of vaporisation of water is 22.5 $\times 10^{5}$ J/Kg?

It means that 22.5 $\times 10^{5}$ J of heat is required to change 1 Kg of water (at its boiling point, 100 $^{\circ}$ C into steam at the same temperature of $100^{\circ}$ C.