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Law of Mass Action

What is minim...

Question

What is minimum mass (in g) of $C a C O_{3} (s)$ will be required to establish the equilibrium $C a C O_{3} (s) ⇌ C a O (s) + C O_{2} (g)$ at $1000 K$ in a $4 L$ container previously containing $C O_{2}$ at $0.82 a t m$ . Equilibrium constant $K_{P}$ for the dissociation reaction $1.64 a t m$ .

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Solution

given in this question
T = 1000K
V = 4L
P = 0.82 atm
R 0.083
Neq = $\frac{P V}{R T}$

Neq = $0.82 \times 4 1000 \times 0.08$
= 0.039
$K p = \frac{α^{2}}{X + α}$
$X + α$ = 0.039
so the mole of calcium carbonate is 0.25
so mass is minimum o.25 * 100
= 25 gm

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