What is molar concentration of $C a (O H)_{2}$ if its solution has pH of $12$ ?

0.01 M

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0.09 M

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0.08 M

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0.02 M

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Solution

The correct option is D 0.02 M
pH+pOH = 14

pOH = 2

pOH $= -$ log[ $O H^{-}$ ]

antilog (-2) = [ $O H^{-}$ ]

= 0.01

1mol $C a (O H)_{2}$ produces 2 mol $O H^{-} =$ 2 x 0.01 =0.02

Hence, the correct option is $D$

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