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Byju's Answer
Standard XII
Chemistry
Ostwald Dilution Law
What is [NH...
Question
What is
[
N
H
+
4
]
in a solution that contain
0.02
M
N
H
3
(
K
b
=
1.8
×
10
−
5
)
and
0.01
M
K
O
H
?
A
9
×
10
−
6
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B
1.8
×
10
−
3
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C
3.6
×
10
−
5
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D
None of these
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Solution
The correct option is
C
3.6
×
10
−
5
Given:
K
b
=
1.8
×
10
−
5
,
N
H
3
=
0.02
,
K
O
H
=
0.01
Solution:
K
O
H
⇔
K
+
+
O
H
−
(KOH is a strong electrolyte)
At eq 0.01 0 0
(Ammonia is a weak electrolyte)
N
H
3
+
H
2
O
(
l
)
⇔
N
H
+
4
(
a
q
)
+
O
H
−
(
a
q
)
(0.02-x) x (0.01+ x) (at equillibrium)
Here the value of x is very less than 0.01. So we can neglect the value of x.
Then, (0.01-x) is changed to 0.01 and (0.02-x) is changed to 0.02
K
b
=
0.01
×
x
0.02
x
=
1.8
×
10
−
5
×
2
=
3.6
×
10
−
5
Hence the
correct option is C.
Suggest Corrections
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Similar questions
Q.
What is
[
N
H
+
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]
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N
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(
K
b
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1.8
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10
−
5
)
and
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Q.
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