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Ideal Gas Equation

What is not Z...

Question

What is not Zero for Elementary substances at their standard state?

A

S⁰

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B

H⁰

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C

G⁰

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D

Both H⁰ and S⁰

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Solution

The correct option is A
S⁰

Entropy is Zero only at Absolute Zero.

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Similar questions

Q. Assertion :Enthalpy and entropy of any elementary substance in their standard states are taken as zero.
Because Reason: At absolute zero, particles of the perfectly crystalline substance become completely ordered.

Q. Calculate the standard free energy change for the reaction,

N_{2} (g) + 3 H_{2} (g) \to 2 N H_{3} (g) a t 298 K .

△ H^{o} = - 92.4 k J m o l^{- 1}

△ S^{o} = - 198.3 J K^{- 1} m o l^{- 1}

Q. Predict the direction in which

△ G^{0}

for the equilibrium

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g); △ G_{298}^{0} = - 33.32 k J

will change with increase in temperature. Calculate

△ G^{0}

500^{\circ} C

△ H

△ S

do not change with temperature, that is,

△ H_{298}^{0} = △ H_{793}

△ S_{298}^{0} = △ S_{793}

△ H^{0} = - 92.38 k J

△ S^{0} = - 198.2 J / K

(The eqn. shifts to left with increase in temp.,

+ 60.83 k J

Q. The equilibrium constant for the reaction given below is

2.0 \times 10^{- 7}

at 300 K. Calculate the standard free energy change for the reaction;

P C l_{5 (g)} ⇌ P C l_{3 (g)} + C l_{2 (g)}

Also, calculate the standard entropy change if

△ H^{o} = 28.40 k J m o l^{- 1} .

Q. Assertion :The enthalpy of both graphite and diamond is taken to be zero, being elementary substances. Reason: The enthalpy of formation of an elementary substance in any state is taken as zero.

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