What is oxidation state of sulphur in the following:
(i) $S O_{2}$ (ii) PbS

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Solution

(i) Calculation of oxidation state of sulphur in $S O_{2}$ :
$Oxidation state of S + (2 \times oxidation state of oxygen) = 0$
$x + (2 \times - 2) = 0$
$x - 4 = 0$
$x = + 4$
Oxidation state of sulphur in sulphur dioxide is +4.

(ii) Calculation of oxidation state of sulphur in $P b S$ :
$Oxidation state of Pb + oxidation state of S = 0$
$+ 2 + x = 0$
$x = - 2$
Oxidation state of sulphur in lead sulphate is -2.

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