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Question

What is pH of 50 ml 0.05 (M) NaOH and 50 ml 0.1 (N)
CH3COOH
pKa=4.73

A
4.63
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B
4.73
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C
3.73
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D
4.83
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Solution

The correct option is C 3.73
NaOH + CH3COOH CH3COONa+H2O
2.5 5 0 Milli mole before reaction
2.5 – 2.5 5 – 2.5 2.5 Milli mole before reaction
Concentration of CH3COOH=2.5×103100×103=2.5×102M
Concentration of CH3COONa is also 2.5×102m
Applying henderson's equation pH=pKa+log[Salt][Acid]=4.73

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