What is pH of 50 ml 0.05 (M) NaOH and 50 ml 0.1 (N) CH3COOH pKa=4.73
A
4.63
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B
4.73
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C
3.73
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D
4.83
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Solution
The correct option is C 3.73 NaOH + CH3COOH→CH3COONa+H2O 2.5 5 0 Milli mole before reaction 2.5 – 2.5 5 – 2.5 2.5 Milli mole before reaction Concentration of CH3COOH=2.5×10−3100×10−3=2.5×10−2M Concentration of CH3COONaisalso2.5×10−2m Applying henderson's equation pH=pKa+log[Salt][Acid]=4.73