What is pH of the half-cell P t - H 2 g - H -if E H - H 2-0-0295 V

E_H^+|H_2 = nbsp; E^∘_H^+|H_2 0.05911 log 1[H^+] = 0.0295 = 0 0.05911×pH pH = 0.02950.0591 = 12=0.5 V ...

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What is pH of...

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What is pH of the half-cell $P t | H_{2} (g) | H^{+}$ if $E_{H^{+} | H_{2}}^{\circ} = - 0.0295 V$

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