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Question

What is phase difference between displacement and acceleration of a particle executing simple harmonic motion

A
π2
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B
2π3
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C
π
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D
3π
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Solution

The correct option is C π
Y=asin(wt+θ)
on differentiation,
v=awcos(wt+θ)
again differentiation u will get,
a=aw2sin(wt+θ)
now take the minus sign inside asπ
a=aw2sin(wt+θ+π)
So phase difference between displacement and acceleration will be,
= wt + \theta + π —{ wt + \theta }
=wt+θ+πwtθ
=π
Hence,
option (C) is correct answer.

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