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Intersection of Sets

What is proba...

Question

What is probability of getting a sum $9$ from two throws of a dice?

\frac{1}{6}

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\frac{1}{8}

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\frac{1}{9}

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\frac{1}{12}

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Solution

The correct option is B $\frac{1}{9}$
Two dice were thrown.
Total outcomes: $36$
Outcomes with total as $9$ are: $4 \to {(3, 6), (4, 5), (5, 4), (6, 3)}$
Required probability:
$P = \frac{4}{36} = \frac{1}{9}$

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Similar questions

In a single throw of dice,what is the probability of getting a sum of 9?

1, 2, 3, 4, 5

6

\frac{1 - k}{6}, \frac{1 + 2 k}{6}, \frac{1 - k}{6}, \frac{1 + k}{6}, \frac{1 - 2 k}{6}

\frac{1 + k}{6}

9

\frac{1}{9}

\frac{2}{9}

k

Outcome	1	2	3	4	5	6
Number of times	8	9	6	7	12	8

\frac{12}{25}

\frac{3}{50}

\frac{1}{8}

\frac{1}{2}

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