What is probability to tend a family with $2$ boys among all the families having $3$ children?

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Solution

Among 3 children
$given 2 should be boys so other will be 0 girl ( Probanility that child is a boy (or) a girl is \frac{1}{2})$

$s o P = \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = \frac{1}{8}$
He boy girl
should
be a boy

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What is probability to tend a family with 2 boys among all the families having 3 children?

Among 3 children given 2 should be boys so other will be 0 girl ( Probanility that child is a boy (or) a girl is12) soP=12×12×12=18 He boy girl should be a boy

What is probability to tend a family with $2$ boys among all the families having $3$ children?

Among 3 children
$given 2 should be boys so other will be 0 girl ( Probanility that child is a boy (or) a girl is \frac{1}{2})$

$s o P = \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = \frac{1}{8}$
He boy girl
should
be a boy