What is $S_{6}$ of the geometric progression $6, 12, 24...$ ?

178

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278

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378

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478

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Solution

The correct option is C $378$
Given series is $6, 12, 24, . . . .$
Here $a = 6, r = 2, n = 6$
$S_{n} = \frac{a_{1} (r^{n} - 1)}{r - 1}$
$S_{6} = \frac{6 ((2)^{6} - 1)}{2 - 1}$
$= \frac{6 (63)}{1}$
$= 378$

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