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Question
What is scalar product ?
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Solution
a.b=|a|×|b|×cos(θ)
Where :
|a| is the magnitude (length) of vector a
|b| is the magnitude (length) of vector b
θ is the angle between a and b
For Example
A.B=(2i−3j).(−4i+2j)=2.(−4)+(−3).2=−8−6=−14
a.b=|a|×|b|×cos(θ)
Where :
|a| is the magnitude (length) of vector a
|b| is the magnitude (length) of vector b
θ is the angle between a and b
For Example
A.B=(2i−3j).(−4i+2j)=2.(−4)+(−3).2=−8−6=−14
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