What is ${sin}^{2} 20^{o} + {sin}^{2} 70^{o}$ equal to?

1

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0

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- 1

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\frac{1}{2}

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Solution

The correct option is A $1$
We know that $sin θ = cos (90^{o} - θ)$ and ${sin}^{2} θ + {cos}^{2} θ = 1$

So ${sin}^{2} (20^{o}) + {sin}^{2} (70^{o}) = {sin}^{2} (20^{o}) + {sin}^{2} (90^{o} - 20^{o}) = {sin}^{2} (20^{o}) + {cos}^{2} (20^{o}) = 1$

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