What is standard gibbs free energy of rxn Zns - Cu2- Zn2- - CusGiven Eo Zn2- -Zn - -0-74 Eo Cu2- -Cu - 0-36

The correct option is B 212.3 kJ E_cell^o = E^o_red = E^o_oxid = 0.36 + 0.74 = 1.10 V Δ G^o = nFE^o = 2 × 96500 × 1.10 J = 212.3 kJ ...

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What is standard gibbs free energy of rxn
$Z n (s) + C u^{2 +} \to Z n^{2 +} + C u (s)$
Given $E^{o} Z n^{2 +} / Z n = - 0.74$ & $E^{o} C u^{2 +} / C u = 0.36$

300 kJ

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212.3 kJ

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200 kJ

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515 kJ

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298 K

Z n / {Z n}^{2 +} (a q) (1 M) / / {C u}^{2 +} (a q) (1 M) / C u

\to E^{o} {Z n}^{2 +} / Z n = - 0.761 V, E^{o} {C u}^{2 +} / C u = + 0.339 V

298 K

Z n / Z n^{2 +} (a = 0.1) / / C u^{2 +} (a = 0.01) / C u

E_{Z n^{2 +}}^{o} / Z n = - 0.762 V

E_{C u^{2 +}}^{o} / C u = + 0.337 V

Z n_{(s)} + C u_{(a q)}^{2 +} \to C u_{(s)} + Z n_{(a q)}^{2 +}

Δ_{f} G^{\circ}

C u_{(a q)}^{2 +}

Z n_{(a q)}^{2 +}

^{- 1}

^{- 1}

For cell reaction, $Z n + C u^{2 +} \to Z n^{2 +} + C u,$ cell representation is

E_{C e l l}^{o}

Z n (s) + C u^{2 +} (a q) \to Z n^{2 +} (a q) + C u (s)

E_{C u^{2 +} / C u}^{\circ} = 0.34 V, E_{Z n^{2 +} / Z n}^{\circ} = - 0.76 V

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