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Question

What is sum of 30 terms of the given arithmetic series: 12+24+36+...?

A
2580
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B
3580
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C
4580
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D
5580
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Solution

The correct option is B 5580
Sn=n2[2a+(n1)d]
S30=302[2×12+(301)12]
S30=15[24+348]
S30=15[372]
S30=5580

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