What is sum of all the isomeric aromatic compounds of the formula $B_{3} N_{3} H_{n} C l_{(6 - n)}$ (isomeric chloro substituted inorganic benzene), where n belongs to [0,6] ?

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Solution

$B_{3} N_{3} H_{6} = 1 a n d B_{3} N_{3} H_{5} C l = 2$

$B_{3} N_{3} H_{4} C l_{2} = 4$

$B_{3} N_{3} H_{3} C l_{3} = 6$

$B_{3} N_{3} H_{2} C l_{4} = 4$

$B_{3} N_{3} H C l_{5} = 2 a n d B_{3} N_{3} C l_{6} = 1$

Total 1 + 2 + 4 + 6 + 4 + 2 + 1 = 20

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