What is the $30^{t h} t e r m$ of the series:
$1 + 5 + 12 + 22 + 35 + . . . . . . . . . . . . . . .$

1335

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1185

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1275

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1295

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Solution

The correct option is A $1335$
Let $S_{30} = 1 + 5 + 12 + 22 + 35 + . . . . + t_{29} + t_{30} S_{30} = 1 + 5 + 12 + 22... + t_{28} + t_{29} + t_{30}$
Subtracting $0 = 1 + 4 + 7 + 10 + 13..... t_{30}$
$\Rightarrow t_{30} =$ Sum of $30$ term having $a = 1, d = 3$
$= \frac{30}{2} 2 N + (30 - 1)^{3} = 15 (2 + 87) = 15 \times 89$
$t_{30} = 1335$

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What is the 30thterm of the series:1+5+12+22+35+...............

The correct option is A 1335Let S30=1+5+12+22+35+....+t29+t30S30=1+5+12+22...+t28+t29+t30Subtracting 0=1+4+7+10+13.....t30⇒t30= Sum of 30 term having a=1,d=3=3022N+(30−1)3=15(2+87)=15×89t30=1335

What is the $30^{t h} t e r m$ of the series:
$1 + 5 + 12 + 22 + 35 + . . . . . . . . . . . . . . .$