What is the 5th and 6th coordination number of compound xy where x are in octahedral voids and y forms fcc lattice

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In which of the following structures coordination number for cations and anions in the packed structure will be same ?

(a) $C l^{-}$ ions form fcc lattice and $N a^{+}$ ions occupy all octahedral voids of the unit cell

(b) $C a^{2 +}$ ions form fcc lattice and $F^{-}$ ions occupy all the eight tetrahedral voids of the unit cell

(d) $S^{2 -}$ ions form fcc lattice and $Z n^{2 +}$ ions go into alternate tetrahedral voids of the unit cell

Q. In a compound, oxides ions form fcc lattice, whereas

\frac{1}{4} t h

of tetrahedral voids are occupied by cations

A^{2 +}

and

\frac{1}{8} t h

of octahedral voids are occupied by cations

B^{3 +}

ions. The simplest formula of the compound is

A compound formed by elements X, Y, Z . Atoms of Y forms ccp lattice and X occupies half the octahedral voids and Z occupies half the tetrahedral voids. Find the formula of the compound?

Q. There are three ionic compounds, first compound has fcc lattice of anions and cations are present in all tetrahedral voids, second compound has fcc lattice of anions and cations are present in all octahedral voids and the third compound has simple cubical lattice in which cubical void is occupied by cation, then the order of packing efficiency of these will be :

Q. Oxide ion forming a fcc lattice in which

F e^{2 +}

ions are occupying

1 / 8^{t h}

of tetrahedral void and

F e^{3 +}

ions are occupying

\frac{1}{2}

of the octahedral void. What will be the formula of the compound?

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