What is the 5th term from the end of the AP 2, 7, 12, ..., 47?

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Solution

AP 2, 7, 12, ..., 47

a = 47

last term , l = 47

d = 7 - 2 = 5

We know nth term from the end,

$a_{n} = l - (n - 1) d a_{5} = 47 - (5 - 1) 5 = 47 - 4 \times 5 = 47 - 20 = 27$

5th term from the end is 27

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