Question

What is the 8th term in the sequnce given below:
$\frac{1}{8},\frac{1}{4},\frac{3}{8},\frac{1}{2},\frac{5}{8},...$ ?

• A. $\frac{9}{8}$
• B. $\frac{7}{8}$
• C. 1
• D. 4

Answer 1

The correct option is C 1

The sequence is:
$\frac{1}{8},\frac{1}{4},\frac{3}{8},\frac{1}{2},\frac{5}{8},...$

Starting from the left,
$\text{First term:}\frac{1}{8}\text{Second term:}\frac{1}{4}=\frac{2}{8}\text{Third term:}\frac{3}{8}\text{Fourth term:}\frac{1}{2}=\frac{4}{8}\text{Fifth term:}\frac{5}{8}$

We can observe that the numerator is increased by 1 for each term.

So, the 8th term will be:
$\frac{8}{8}\text{or}1$