Question

What is the acceleration due to gravity on the top of Mount Everest ? Mount Everest is the highest mountain peak of the world at the height of 8848 m. The value at sea level is 9.80 $m{s}^2$

Answer 1

Given,

$h=8848m$

The value of sea level is $9.08m/s^2$

So,

Let $g^{\prime }$ be the acceleration due to the gravity on the Mount Everest.

$g^{\prime }=g(1-\frac{2h}{h})$

$=9.8(1-\frac{17696}{6400000})$

$=9.8(1-0.00276)$

$9.8\times 0.99724$

$=9.773m/s^2$

Thus, the acceleration due to gravity on the top of Mount Everest is $=9.773m/s^2$