Question

What is the action of the following reagent on ethanoic acid?
$LiAl{H}_4/H_3{O}^{+}$.

Answer 1

Lithium aluminum hydride reduces ethanoic acid (acetic acid) to ethanol.

$\underset{\text{ethanoic acid}}{C{H}_3-COOH}\underset{2)H_3{O}^{+}}{\overset{1)LiAl{H}_4,\text{ether}}{\to }}\underset{\text{ethanol}}{C{H}_3-C{H}_2-OH}$