What is the active mass of $5.6$ litres of $O_{2}$ at S.T.P?

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Solution

Moles = $\frac{5.6}{22.4}$ = 0.25 moles

Moles = $\frac{M a s s}{M o l e c u l a r m a s s}$

0.25 = $\frac{M a s s}{32}$

Mass = $0.25 \times 32$ = 8g

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What is the active mass of 5.6 litres of O2 at S.T.P?

Moles = 5.622.4 = 0.25 moles Moles =MassMolecular mass 0.25 = Mass32 Mass = 0.25×32 = 8g

What is the active mass of $5.6$ litres of $O_{2}$ at S.T.P?

Moles = $\frac{5.6}{22.4}$ = 0.25 moles

Moles = $\frac{M a s s}{M o l e c u l a r m a s s}$

0.25 = $\frac{M a s s}{32}$

Mass = $0.25 \times 32$ = 8g