Question

What is the additive inverse of $-\left(-\frac{2}{3}\right)$?

Answer 1

Additive inverse of a number:

The value of an additive inverse of a number is defined as the value that when added to the original number, the result should be zero.

Let $n$is any given number. Then, the additive inverse of number $n$will be $-n$because $n+(-n)=0$.

The additive inverse of a number has always the opposite sign as the sign of the given number.

We have to find the additive inverse of $-\left(-\frac{2}{3}\right)$.

$-\left(-\frac{2}{3}\right)=\frac{2}{3}\left[\because (-)\times (-)=(+)\right]$

So, the additive inverse of a number $\frac{2}{3}$is $\left(-\frac{2}{3}\right)$ because $\frac{2}{3}+\left(-\frac{2}{3}\right)=0$.

Hence, the additive inverse of $\frac{2}{3}$is $-\frac{2}{3}$.