Question

What is the additive inverse of $\frac{-6}{-15}$?

Answer 1

Additive inverse of a number:

The value of an additive inverse of a number is defined as the value that when added to the original number, the result should be zero.

Let $n$is any given number. Then, the additive inverse of number $n$will be $-n$because $n+(-n)=0$.

The additive inverse of a number has always the opposite sign as the sign of the given number.

We have to find the additive inverse of $\frac{-6}{-15}$.

$\frac{-6}{-15}=\frac{6}{15}$

So, the additive inverse of a number $\frac{6}{15}$is $-\frac{6}{15}$ because $\frac{6}{15}+\left(-\frac{6}{15}\right)=0$.

Hence, the additive inverse of $\frac{-6}{-15}$is $-\frac{6}{15}$.