What is the additive inverse of the complex number $6 + 7 i$ ?

6 - 7 i

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6 + 7 i

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 6 + 7 i

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 6 - 7 i

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $- 6 - 7 i$
Given: $6 + 7 i$
The additive inverse of a complex number is the negative of the complex number.
$\Rightarrow - (6 + 7 i) = - 6 - 7 i$

Suggest Corrections

Similar questions

4 - 3 i

(i) z_{1} - (z_{2} + z_{3}) = (z_{1} - z_{2}) + z_{3}

(i i)

i^{4}, i^{6}, i^{68} & i^{222}

(i i i)

\frac{4}{i} + \frac{3}{i^{3}}

(i v)

z_{1} = 4 + 2 i, z_{2} = 3 + 7 i,

2 z_{1} - z_{2} = 5 + 3 i .

What is the additive inverse of $6$ ?

What is additive inverse of a number? What is the additive inverse of $7$ and $- 5$ ?

Join BYJU'S Learning Program