Question

What is the amount of energy released when 1 a.m.u. of mass is lost? Express the energy in terms of MeV.

• A. 932.58

Answer 1

The correct option is A 932.58
Given:

$1\text{a.m.u.}$ of mass is lost, i.e. $\Delta \text{m}$$=1\text{a.m.u.}=1.66\times {10}^{-27}\text{kg}$

We know, $\text{E}=\Delta {\text{mc}}^2$

$\text{E}=1.66\times {10}^{-27}\text{kg}\times$$(3\times {10}^8{\text{m s}}^{-1}{)}^2$

$\text{E}=1.494\times {10}^{-10}\text{J}$

$1\text{MeV}=1.602\times {10}^{-13}\text{J}$

$⟹\text{E}=\frac{(1.494\times {10}^{-10})}{(1.602\times {10}^{-13})}$

$=932.58\text{MeV}$