Question

What is the amount of heat required to convert 1kg of ice at -10 degree Celsius into steam at 100 degree Celsius at normal pressure.

Answer 1

Dear Student
in this question you just have know the step how ice is converting

steps

1 -10 ice to 0 ice

2 0 ice to 0 water.this is the process of phase change temperature remain constant in this process but heat is taken.

3 convert 0 water to 100 water

4 100 water to 100. steam this is the process of phase change temperature remain constant in this process but heat is taken.

so total heat required =heat taken to convert -10 ice to 0 ice +heat taken to convert 0ice to 0 water +heat taken to convert 0 water to 100 water +heat taken to convert 100 water to 100 steam

heat taken to convert -10 ice to 0 ice =mc_iceΔt

c_ice=specific heat of ice =2.05J/gC

Δt=change in temperature=10

m=1000 g

put these values

heat taken to convert -10 ice to 0 ice =mc_iceΔt=20,500J

heat taken to convert 0 ice to 0 water=mH_f

H_f =heat of fusion=333.5J/g

put these values

heat taken to convert 0 ice to 0 water=mH_f=3,33,500J

heat taken to convert 0 water to 100 water =mc_waterΔt

c_ice=specific heat of water =4.178J/gC

Δt=change in temperature=100

m=1000g

put these values

heat taken to convert 0 ice to 100 ice =mc_waterΔt=4,17,800J

heat taken to convert 100 water to 100 steam =mH_v

H_v =heat of vaporization =2257J/g

put these values

heat taken to convert 100 water to 100 steam =mH_v=22,57,000J

so total heat required =20,500J+3,33,500+4,17,800+22,57,000=30,28,800J = 3,028.8 KJ

Regards