Question

What is the amount of the heat necessary to raise the temperature of $50.0$ grams of liquid water from ${10.0}^{\circ }C$ to ${30.0}^{\circ }C$.

(The specific heat of water liquid is $4.18J/g{/}^{\circ }C$)

• A. $20J$
• B. $80J$
• C. $100J$
• D. $200J$
• E. $4,180J$

Answer 1

Answer: (E)

$4,180J$

The amount of the heat necessary to raise the temperature of 50.0 grams of liquid water from 10.0 deg C to 30.0 deg ${}^{o}C$ is obtained by multiplying the mass of water with a specific heat of water and the temperature change.
It is $Q=mS\Delta T=50.0\times 4.18\times (30.0-10.0)=4180J$
Note : The specific heat of water liquid is 4.18 J/g / ${}^o$C.