What is the amount of urea dissolved per litre, if aqueous solution is isotonic with $10$ % cane sugar solution: (mol. wt. of urea $= 60$ )?

200 g / L

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19.2 g / L

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17.54 g / L

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16.7 g / L

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Solution

The correct option is C $17.54 g / L$
Isotonic solutions have same osmotic pressure.
$\frac{W_{1}}{m o l . w t . \times V_{1}} = \frac{W_{2}}{m o l . w t . \times V_{2}}$
Given, $W_{1} = ?, W_{2} = 10 g$ ,
$V_{1} = 1 L, V_{2} = 100 m L = 0.1 L$
$M o l . w t ._{1}$ (mol. wt. of urea) $= 60$
Mol. $w t ._{2}$ (mol. wt. of cane sugar) $= 342$
$∴ \frac{W_{1}}{60 \times 1} = \frac{10}{342 \times 0.1}$
$∴ W_{1} = \frac{60 \times 10}{342 \times 0.1} = 17.54 g / L$

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Similar questions

Q. A

10

% aqueous solution of cane sugar (mol. wt.

342

) is isotonic with

1.754

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Q. The boiling points for aqueous solutions of sucrose and urea are same at constant temperature. If 3 g of urea is dissolved in its 1 L solution, what is the weight of sucrose dissolved in its 1 L solution ?
[Urea = 60 Wmol, sucrose = 342 g/mol]

Q. If a

100 m L

of urea solution is isotonic with

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solution of cane sugar , then calculate the weight of urea in the urea solution
Given: The molecular mass of cane sugar is

342 g m o l^{- 1}

and that of urea is

60 g m o l^{- 1}

The concentration in gms per litre of a solution of cane sugar (M=342) which is isotonic with a solution containing 6 gms of urea (M = 60) per litre is:

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What is the amount of urea dissolved per litre, if aqueous solution is isotonic with 10% cane sugar solution: (mol. wt. of urea =60)?

The correct option is C 17.54 g/LIsotonic solutions have same osmotic pressure.W1mol.wt.×V1=W2mol.wt.×V2Given, W1=?,W2=10 g,V1=1 L,V2=100 mL=0.1 LMol.wt.1 (mol. wt. of urea) =60Mol. wt.2 (mol. wt. of cane sugar) =342∴W160×1=10342×0.1∴W1=60×10342×0.1=17.54 g/L

What is the amount of urea dissolved per litre, if aqueous solution is isotonic with $10$ % cane sugar solution: (mol. wt. of urea $= 60$ )?