What is the amount of water required for a workable RC of mix 1 : 2 : 4 by weight, when W/C is 0.60 and unit weight of concrete is $2400 k g / m^{3}$ ?

165 lit.

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205 lit.

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245 lit.

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285 lit.

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Solution

The correct option is B 205 lit.
Ans (b)

Unit weight of concrete = 2400 kg/m3

Cement is 1/7th part of the mix by weight as the ration of the RC is 1:2:4.

So the total quantity of cement in 1 cu.m concrete = 2400 / 7 = 343 kg

Given water/cement ratio = 0.6

So quantity of water = 0.6 * one unit of cement = 0.6 * 343 = 206 kg of water.

Assuming that 1 kg of water is equal to 1 litre, the total water required for the desired mix will be 206 litres.

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What is the amount of water required for a workable RC of mix 1 : 2 : 4 by weight, when W/C is 0.60 and unit weight of concrete is 2400 kg/m3?

What is the amount of water required for a workable RC of mix 1 : 2 : 4 by weight, when W/C is 0.60 and unit weight of concrete is $2400 k g / m^{3}$ ?