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Question

What is the amount of work done by a weight-lifter in holding a weight of 100 kg on his shoulders for 40 s?


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Solution

Step 1: Given data

Mass of weight, m=100kg

Time, t=40s

Since the weightlifter does not move, it can be said that displacement is S=0.

Step 2: Calculating work done

Work done is given by,

W=FS

Where, F is force and S is displacement.

Substituting the known values, we get,

W=F×0W=0Joule

The amount of work done by a weight-lifter in holding a weight of 100 kg on his shoulders for 40 seconds will be zero as there is no net displacement.


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