Question

What is the angle at which hands of a clock are inclined at 15 minutes past 5?

• A. 58
• B. 64
• C. 78
• D. 72
• E. 67

Answer 1

The correct option is E

67

Angle traced by hour hand in $\frac{21}{4}$ hrs = ${(\frac{360}{12}\times \frac{21}{4})}^0$= 157.5${}^0$

Angle traced by minute hand in 15 min. = ${(\frac{360}{60}\times 15)}^0$ = 90${}^0$

$\therefore$ Required angle = ${\left(157\frac{1}{2}\right)}^0-{90}^0=67{\frac{1}{2}}^0$