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Question

What is the angle between the following pair vectors? A=^i+^j+^k and B=2^i2^j2^k


A

30

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B

60

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C

90

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D

180

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Solution

The correct option is D

180


A.B=AB cos θ=A.BABBut, A.B=(^i+^j+^k).(2^i2^j2^k)A.B=222=6Again A=|A|=(1)2+(1)2+(1)2=3B=|B|=(2)2+(2)2+(2)2=12=23Now, cos θ=63×23=1θ=180


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