What is the angle between two centriole of a centrosome?

30^{o}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

45^{o}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

60^{o}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

90^{o}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $90^{o}$
The centrosome is located in the cytoplasm usually close to the nucleus. It maintains the equal distribution of chromosomes during cell division.
It consists of two centrioles oriented at right angles or 90 $^{o}$ to each other.
So, the correct answer is option D.

Suggest Corrections

Similar questions

\frac{{tan}^{2} 60^{o} + 4 {sin}^{2} 45^{o} + {sin}^{2} 90^{o}}{3 {sec}^{2} 30^{o} + {csc}^{2} 60^{o} - {cot}^{2} 30^{o}}

\frac{{tan}^{2} 60^{o} + 4 {cos}^{2} 45^{o} + 3 {sec}^{2} 30^{o} + 5 {cos}^{2} 90^{o}}{c o sec 30^{o} + sec 60^{o} - {cot}^{2} 30^{o}}

4 ({sin}^{4} 30^{o} + {cos}^{4} 60^{o}) - 3 ({cos}^{4} 45^{o} - {sin}^{2} 90^{o})

\frac{x {cosec}^{2} 30^{o} {sec}^{2} 45^{o}}{8 {cos}^{2} 45^{o} {sin}^{2} 90^{o}} = {tan}^{2} 60^{o} - {tan}^{2} 45^{o}

x

{cot}^{2} 60^{o} + {sin}^{2} 45^{o} + {sin}^{2} 30^{o} + {cos}^{2} 90^{o} = \frac{13}{12}

Join BYJU'S Learning Program