What is the angle between A- and the resultant of A- -B- and A- -B-

If the vectors $\to a$ and $\to b$ are perpendicular to each other, then a vector $\to v$ in terms of $\to a$ and $\to b$ satisfying the equations
$\to v . \to a = 0, \to v . \to b = 1 a n d [\to v \to a \to b] = 1$ is

The scalars l and m such that $l \to a + m \to b = \to c$ where $\to a, \to b$ and $\to c$ are given vectors, are equal to

Q. If

\to A \times \to B = \to B \times \to A

, then the angle between

A

and

B

Q. lf

\to A

and

\to B

denote the sides of a parallelogram and its area is

\frac{1}{2} | A | | B |

The angle between

\to A

and

\to B

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What is the angle between →A and the resultant of (→A+→B) and (→A−→B)

The correct option is A 0oResultant →R=(→A+→B)+(→A−→B)=2→ALet angle between →A and →R is θ. ⇒→A×→R=|→A||→R|sinθ⇒→A×2→A=|→A||2→A|sinθ=0 ⇒sinθ=0 ⇒θ=0o

What is the angle between $\to A$ and the resultant of $(\to A + \to B)$ and $(\to A - \to B)$