Question

What is the angle between $\overrightarrow{P}$ and the resultant of $(\overrightarrow{P}+\overrightarrow{Q})$ and $(\overrightarrow{P}-\overrightarrow{Q})$?

• A. zero
• B. $ta{n}^{-1}\frac{P}{Q}$
• C. $ta{n}^{-1}\frac{Q}{P}$
• D. ${\tan }^{-1}\left(\frac{P-Q}{P+Q}\right)$

Answer 1

The correct option is A zero

The resultant of $\overrightarrow{P}+\overrightarrow{Q}$ and $\overrightarrow{P}-\overrightarrow{Q}$ gives $2\overrightarrow{P}$ vector which is in the direction of $\overrightarrow{P}$.