Question

What is the angle of dip at a place where the horizontal component of the earth's magnetic field is equal to the vertical component?

Answer 1

Step 1: Formula used

The angle of dip, $\mathrm{\delta }={\tan }^{-1}\left(\frac{{\mathrm{B}}_{\mathrm{v}}}{{\mathrm{B}}_{\mathrm{h}}}\right)$

Where,

B_v is the vertical component of the earth's magnetic field.

B_h is the horizontal component of the earth's magnetic field.

Here,

${\mathrm{B}}_{\mathrm{v}}={\mathrm{B}}_{\mathrm{h}}$

Step 2: Finding the angle of dip

By using the formula, we get

$$\begin{gathered} \mathrm{\delta }={\tan }^{-1}\left(1\right) \\ =45° \end{gathered}$$

Therefore, the angle of dip at a place where the horizontal component of the earth's magnetic field is equal to the vertical component is $45°$.